The maximum area of a parallelogram inscribed in a triangle $ABC$ (given that $A$ is also one of the vertices of the parallelogram) is equal to (where symbols have their usual meaning in $\Delta ABC$):

  • A
    $\frac{bc}{8} \sin A$
  • B
    $\frac{bc}{2} \sin A$
  • C
    $\frac{bc}{4} \sin A$
  • D
    $\frac{bc}{3} \sin A$

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